Momentum, Impulse, and the Impulse-Momentum Theorem. Linear momentum is the product of a system's mass and its velocity. In equation form, linear momentum p is. p = mv. p = m v. You can see from the equation that momentum is directly proportional to the object's mass ( m) and velocity ( v ). Therefore, the greater an object's mass or the Q.7 A 50 kg man with 20 kg load on his head climbs up 20 steps of 0.25 m height each. The work done by the man on the block during climbing is (A)5J (B) 350J (C) 1000 J (D) 3540J 25): We will calculate the work required to lift the bucket intact, less the work not done because of the leak. We will have to use the acceleration due to gravity because this is a metric units problem. The work for the intact bucket is 20(40)9.8 = 7840 joules. For the work not done, ∆m = 5− t 2 ∆F = (5− t 2)9.8 ∆W = (5− t 2)9.8∆ Chapter 7- Homework. Now let's consider the total work done on an object that has several forces acting on it. A tractor is hitched to a sled loaded with firewood and pulls the sled a distance of 20.0 m along level frozen ground (Figure 1). The total weight of the sled and load is 14,700 N. The tractor exerts a constant force F⃗ T with
Load is the resistance to be overcome by the machine. the effort is the force required to overcome the resistance to get the work done by the machine. This method of determining velocity ratio is used for various pulley systems considered here. 1. First Order Pulley System. A first-order pulley system is shown in the below figure.

A mass of 1000 kg is lifted 10 m in 10 seconds. The work done can be calculated as. W = (1000 kg) (9.81 m/s 2) (10 m) = 98100 J (Nm) The power required is work done per unit time. P = (98100 J) / (10 s) = 9810 W (J/s) = 9.8 kW. Example - Work done by an Electric Motor. The work done by a 1 kW electric motor in 1 hour can be calculated by

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    • find the work done when a 25 kg weight